# Line slope calculator 5x+y=28

**Straight line given by points A[4; 8] and B[5; 3]**

## Calculation:

**Slope-intercept form of line:**y = -5x+28

**Canonical form of the line equation:**5x+y-28 = 0

**Parametric form of the line equation:**

x = t+4

y = -5t+8 ; t ∈ R

**Slope:**m = -5

**Slope angle of line: φ =**-78°41'24″ = -1.3734 rad

**X intercept:**x

_{0}= 5.6

**Y intercept:**y

_{0}= q = 28

**Distance line from the origin:**d

_{0}= 5.4913

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(1; -5)

**Normal vector: n =**(5; 1)

**Midpoint of the segment AB: M =**[4.5; 5.5]

**Perpendicular Bisector equation:**x-5y+23 = 0

**Vector OA = (4; 8) ; |OA| = 8.9443**

**Vector OB = (5; 3) ; |OB| = 5.831**

**Scalar product OA .OB = 44**

**Angle ∠ AOB = 32°28'16″ = 0.5667 rad**