# Line slope calculator x+y=8

**Straight line given by points A[0; 8] and B[2; 6]**

## Calculation:

**Slope-intercept form of line:**y = -x+8

**Canonical form of the line equation:**x+y-8 = 0

**Parametric form of the line equation:**

x = t

y = -t+8 ; t ∈ R

**Slope:**m = -1

**Slope angle of line: φ =**-45° = -0.7854 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 5.6569

**The length of the segment AB: |AB| =**2.8284

**Vector: AB =**(2; -2)

**Normal vector: n =**(1; 1)

**Midpoint of the segment AB: M =**[1; 7]

**Perpendicular Bisector equation:**2x-2y+12 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (2; 6) ; |OB| = 6.3246**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 18°26'6″ = 0.3218 rad**