# Line slope calculator x-8y=-31

**Straight line given by points A[1; 4] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.125x+3.875

**Canonical form of the line equation:**x-8y+31 = 0

**Parametric form of the line equation:**

x = 8t+1

y = t+4 ; t ∈ R

**Slope:**m = 0.125

**Slope angle of line: φ =**7°7'30″ = 0.1244 rad

**X intercept:**x

_{0}= -31

**Y intercept:**y

_{0}= q = 3.875

**Distance line from the origin:**d

_{0}= 3.8451

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; 1)

**Normal vector: n =**(1; -8)

**Midpoint of the segment AB: M =**[5; 4.5]

**Perpendicular Bisector equation:**8x+y-44.5 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 29**

**Angle ∠ AOB = 46°54'33″ = 0.8187 rad**