# Line slope calculator x+4y=12

**Straight line given by points A[0; 3] and B[4; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+3

**Canonical form of the line equation:**x+4y-12 = 0

**Parametric form of the line equation:**

x = 4t

y = -t+3 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 12

**Y intercept:**y

_{0}= q = 3

**Distance line from the origin:**d

_{0}= 2.9104

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; -1)

**Normal vector: n =**(1; 4)

**Midpoint of the segment AB: M =**[2; 2.5]

**Perpendicular Bisector equation:**4x-y-5.5 = 0

**Vector OA = (0; 3) ; |OA| = 3**

**Vector OB = (4; 2) ; |OB| = 4.4721**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 63°26'6″ = 1.1071 rad**