# Line slope calculator 2x+3y=20

**Straight line given by points A[1; 6] and B[4; 4]**

## Calculation:

**Slope-intercept form of line:**y = -0.6667x+6.6667

**Canonical form of the line equation:**2x+3y-20 = 0

**Parametric form of the line equation:**

x = 3t+1

y = -2t+6 ; t ∈ R

**Slope:**m = -0.6667

**Slope angle of line: φ =**-33°41'24″ = -0.588 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 6.6667

**Distance line from the origin:**d

_{0}= 5.547

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(3; -2)

**Normal vector: n =**(2; 3)

**Midpoint of the segment AB: M =**[2.5; 5]

**Perpendicular Bisector equation:**3x-2y+2.5 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (4; 4) ; |OB| = 5.6569**

**Scalar product OA .OB = 28**

**Angle ∠ AOB = 35°32'16″ = 0.6202 rad**