# Line slope calculator 5x+3y=48

**Straight line given by points A[6; 6] and B[9; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.6667x+16

**Canonical form of the line equation:**5x+3y-48 = 0

**Parametric form of the line equation:**

x = 3t+6

y = -5t+6 ; t ∈ R

**Slope:**m = -1.6667

**Slope angle of line: φ =**-59°2'10″ = -1.0304 rad

**X intercept:**x

_{0}= 9.6

**Y intercept:**y

_{0}= q = 16

**Distance line from the origin:**d

_{0}= 8.2319

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; -5)

**Normal vector: n =**(5; 3)

**Midpoint of the segment AB: M =**[7.5; 3.5]

**Perpendicular Bisector equation:**3x-5y-5 = 0

**Vector OA = (6; 6) ; |OA| = 8.4853**

**Vector OB = (9; 1) ; |OB| = 9.0554**

**Scalar product OA .OB = 60**

**Angle ∠ AOB = 38°39'35″ = 0.6747 rad**