# Line slope calculator 3x+7y=48

**Straight line given by points A[2; 6] and B[9; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.4286x+6.8571

**Canonical form of the line equation:**3x+7y-48 = 0

**Parametric form of the line equation:**

x = 7t+2

y = -3t+6 ; t ∈ R

**Slope:**m = -0.4286

**Slope angle of line: φ =**-23°11'55″ = -0.4049 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 6.8571

**Distance line from the origin:**d

_{0}= 6.3027

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(7; -3)

**Normal vector: n =**(3; 7)

**Midpoint of the segment AB: M =**[5.5; 4.5]

**Perpendicular Bisector equation:**7x-3y-25 = 0

**Vector OA = (2; 6) ; |OA| = 6.3246**

**Vector OB = (9; 3) ; |OB| = 9.4868**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 53°7'48″ = 0.9273 rad**