# Line slope calculator 3x+2y=28

**Straight line given by points A[4; 8] and B[6; 5]**

## Calculation:

**Slope-intercept form of line:**y = -1.5x+14

**Canonical form of the line equation:**3x+2y-28 = 0

**Parametric form of the line equation:**

x = 2t+4

y = -3t+8 ; t ∈ R

**Slope:**m = -1.5

**Slope angle of line: φ =**-56°18'36″ = -0.9828 rad

**X intercept:**x

_{0}= 9.3333

**Y intercept:**y

_{0}= q = 14

**Distance line from the origin:**d

_{0}= 7.7658

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(2; -3)

**Normal vector: n =**(3; 2)

**Midpoint of the segment AB: M =**[5; 6.5]

**Perpendicular Bisector equation:**2x-3y+9.5 = 0

**Vector OA = (4; 8) ; |OA| = 8.9443**

**Vector OB = (6; 5) ; |OB| = 7.8102**

**Scalar product OA .OB = 64**

**Angle ∠ AOB = 23°37'46″ = 0.4124 rad**