# Line slope calculator 5x-2y=10

**Straight line given by points A[2; 0] and B[4; 5]**

## Calculation:

**Slope-intercept form of line:**y = 2.5x-5

**Canonical form of the line equation:**5x-2y-10 = 0

**Parametric form of the line equation:**

x = 2t+2

y = 5t ; t ∈ R

**Slope:**m = 2.5

**Slope angle of line: φ =**68°11'55″ = 1.1903 rad

**X intercept:**x

_{0}= 2

**Y intercept:**y

_{0}= q = -5

**Distance line from the origin:**d

_{0}= 1.857

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; 5)

**Normal vector: n =**(5; -2)

**Midpoint of the segment AB: M =**[3; 2.5]

**Perpendicular Bisector equation:**2x+5y-18.5 = 0

**Vector OA = (2; 0) ; |OA| = 2**

**Vector OB = (4; 5) ; |OB| = 6.4031**

**Scalar product OA .OB = 8**

**Angle ∠ AOB = 51°20'25″ = 0.8961 rad**