This much I am familiar with. And in essence you are basically saying that a CCS has a high impedance that forms a voltage divider with the load with the lion's share of the current going to the lower impedance portion. Were it practical to do so and if we didn't care about efficiency, an amp with a 100KV supply could use a 10M resistor to much the same effect.
I guess the question is that in a common cathode triode, the lowish plate impedance drives the plate load in parallel with the load. A pentode is the opposite and has a Zout that is PS's Zout in series with the resistor load with the tube modulating the PS. So I am wondering if that resistor load on the pentode is a reasonable and somewhat unexplored way to drive these things or if your above calculation contains something to suggest otherwise.